Project Euler - Problem 6 - Sum Square Difference: Coding Interview Prep (freeCodeCamp)

 Problem 6: Sum square difference

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 − 385 = 2640.

Find the difference between the sum of the squares of the first n natural numbers and the square of the sum.

Solution:

function sumSquareDifference(n) {

  let sum = 0;

  let sqSum = 0;

  for(let i=1;i<=n;i++) {

    sum+=i;

    sqSum+=i*i

  }

  console.log(sum*sum-sqSum)

  return (sum*sum-sqSum);

}

sumSquareDifference(100);

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